38. Function Print1() puts "First" and Function Print2() puts "Second". Print1() is called earlier. What is put to output by calling Print2()?
Answer: B
Print2() outputs "Second".
When Print2() is called, it executes its own code, which is to output "Second". The earlier call to Print1() does not affect the output of Print2().
A) FirstSecond
This option suggests that both outputs from Print1() and Print2() are combined. However, since each function outputs independently, this option is incorrect.
B) Second
This is correct because when Print2() is executed, it solely outputs "Second". The previous output from Print1() does not influence this function's output.
C) First
This option indicates that Print2() would output "First", which is incorrect. Print2() is defined to output "Second", regardless of what Print1() outputs.
D) Second First
This option implies that calling Print2() would result in outputs from both functions in a specific order. However, Print2() only outputs "Second", making this option incorrect.
Conclusion
The correct answer is "Second" because Print2() executes its own defined output independently of any other function calls. All other options fail to accurately represent what Print2() produces when called.