51. Midazolam syrup 2 mg/mL needs to be repackaged into oral syringes each containing 10 mg. How many oral syringes can be prepared using 120 mL of this syrup?
Answer: C
24 oral syringes can be prepared using 120 mL of midazolam syrup.
Each oral syringe requires 10 mg of midazolam, and since the syrup concentration is 2 mg/mL, this means each syringe will need 5 mL of syrup (10 mg ÷ 2 mg/mL = 5 mL). With 120 mL of syrup available, dividing this volume by the required 5 mL per syringe yields 24 syringes (120 mL ÷ 5 mL/syringe = 24 syringes).
A) 5
This option is incorrect because if only 5 syringes were prepared, it would imply that only 25 mL of syrup was used (5 syringes × 5 mL/syringe = 25 mL), which is significantly less than the 120 mL available.
B) 12
This option is also incorrect. If 12 syringes were prepared, that would require 60 mL of syrup (12 syringes × 5 mL/syringe = 60 mL), leaving 60 mL unused from the original 120 mL, which does not utilize the full amount of syrup.
C) 24
This option is correct as calculated. Preparing 24 syringes requires exactly 120 mL of syrup (24 syringes × 5 mL/syringe = 120 mL), which utilizes the entire volume of syrup available.
D) 60
This option is incorrect because preparing 60 syringes would require 300 mL of syrup (60 syringes × 5 mL/syringe = 300 mL), which exceeds the 120 mL available and is thus not feasible.
Conclusion
The correct answer is 24 oral syringes, as this is the maximum number that can be prepared without exceeding the available 120 mL of midazolam syrup. Other options either underutilize the syrup or require more than what is available, demonstrating that option C is definitively correct.