43. Students at a local middle school are selling candy bars for a fund-raiser. The candy bars come packaged in cases of 60 bars, and the school makes a 0.75 profit from each candy bar sold. How many cases of candy bars need to be sold for the school to make a profit of 900?
Answer: C
20 cases of candy bars need to be sold for the school to make a profit of 900.
To achieve a profit of 900, the school must first determine the total number of candy bars that need to be sold. Since each candy bar yields a profit of 0.75, selling 1200 candy bars (900 ÷ 0.75) would be required, which equates to 20 cases (1200 ÷ 60).
A) 8
Selling 8 cases of candy bars would yield a total of 480 bars (8 x 60), resulting in a profit of only 360 (480 x 0.75). This amount falls short of the 900 profit goal, making this option incorrect.
B) 12
If the school sells 12 cases, they would have 720 candy bars (12 x 60), leading to a profit of 540 (720 x 0.75). While this is an improvement over 8 cases, it still does not meet the required profit of 900, thus making this option incorrect.
C) 20
Selling 20 cases results in 1200 candy bars (20 x 60), which provides a profit of 900 (1200 x 0.75). This meets the exact profit target of the fundraiser, confirming that this option is correct.
D) 40
If the school sells 40 cases, they would have 2400 candy bars (40 x 60), producing a profit of 1800 (2400 x 0.75). Although this exceeds the profit goal of 900, it is not the minimum required to reach that target, making this option incorrect.
Conclusion
The calculation confirms that selling 20 cases of candy bars is the precise amount needed to achieve a profit of 900. All other options either fall short of the target or exceed it without being the minimum necessary, thereby validating option C as the definitive correct answer.