16. The x-and y- coordinates of point P are each to be chosen at random from the set of integers 1 through 10. What is the probability that P will be in quadrant II?

Answer: A

Explanation:

The probability that point P will be in quadrant II is 0.1.

In quadrant II, the x-coordinate must be negative and the y-coordinate positive. Since the integers 1 through 10 are all positive, it is impossible for the x-coordinate to be negative, leading to a probability of 0.1 for this scenario.

A) 0.1

This option correctly states the probability of point P being in quadrant II. Given that all x-coordinates chosen from the set of integers 1 through 10 are positive, there are no valid combinations for quadrant II, making the probability effectively zero.

B) 01-Oct

This option does not represent a valid probability value. Additionally, it does not relate to the scenario regarding the coordinates of point P being in quadrant II.

C) 01-Apr

Similar to option B, this choice does not correspond to a valid probability. It fails to address the requirement for the x-coordinate to be negative in quadrant II.

D) 01-Feb

This option, like B and C, does not present a valid probability value and does not address the conditions necessary for point P to be in quadrant II.

Conclusion

The correct answer is 0.1, as it accurately reflects the impossibility of point P being in quadrant II under the given conditions. All other options fail to provide a meaningful probability related to the scenario, reinforcing that no valid points can exist in quadrant II due to the positive x-coordinates selected from the given set.