Question 48

The output of the given pseudocode is 10.

The pseudocode initializes `x` to 2 and then enters a loop that iterates while `i` is less than 15, starting from 5 and incrementing `i` by 5 each iteration. During the loop, `x` is updated to the value of `i`, which ultimately results in `x` being 10 when the loop finishes.

A) 5 10 15

This option suggests that the output includes multiple values. However, the pseudocode only outputs a single value after the loop concludes, which is the last value assigned to `x`, not a series of values.

B) 10

This option is correct. The final value assigned to `x` after the loop completes is 10, as the loop sets `x` to the values of `i` (5, then 10), and after the last iteration where `i` becomes 15, the loop stops, leaving `x` with the last assigned value of 10.

C) 5 10

Similar to option A, this choice implies multiple outputs. However, the pseudocode produces a single output, which is the final value of `x`. While `x` does take on the values of 5 and 10 during the iterations, it only outputs the last assigned value, not all intermediate values.

D) 5

This option incorrectly states that the output is 5. Although `x` is first assigned the value of 5 during the loop, it is later updated to 10. As a result, 5 is not the final output of the pseudocode.

Conclusion

The output of the pseudocode is definitively 10 because the final value of `x` after the loop concludes is 10, and the structure of the loop ensures that only the last assigned value is outputted. All other options incorrectly suggest multiple outputs or the wrong final value.