Question 8

The output of the algorithm is 11.

The algorithm calculates how many times the value of `d` (which is 6) can be subtracted from `n` (which is 61) until `n` is less than `d`. In this case, the result of the iterations leads to a final count of 11.

A) 10

Option A is incorrect because if we subtract 6 from 61 repeatedly, we find that 10 subtractions would only yield a total of 60, leaving a remainder of 1 for `n`. Therefore, the count of 10 does not fully encompass the total possible subtractions.

B) 11

Option B is correct as the algorithm correctly counts the number of times 6 can be subtracted from 61. The sequence of subtractions (61, 55, 49, 43, 37, 31, 25, 19, 13, 7, 1) shows that 6 can be subtracted 11 times before `n` becomes less than `d`.

C) 15

Option C is incorrect because subtracting 6 from 61 cannot yield 15 iterations. If we attempted to subtract 6 fifteen times, it would require 90, which exceeds the original value of `n`.

D) 16

Option D is also incorrect as the same reasoning applies; subtracting 6 from 61 sixteen times would require a total of 96, which is not possible. Therefore, it cannot be the result of the algorithm.

Conclusion

The output of 11 is confirmed as the correct answer since it accurately represents the number of times 6 can be subtracted from 61 without resulting in a negative value. All other options fail to meet this criterion, either by exceeding the original value or miscalculating the iterations.