29. In an experiment, a student tests three unknown fluids with the following measurements: Fluid A: m=2060g, V=2000mL, Fluid B: m=672g, V=850mL, and Fluid C: m=990g, V=1100mL. Arrange the liquids in the correct order of how they would separate in a beaker from bottom to top.
Answer: B
B, C, A
The correct order for the fluids to separate in a beaker from bottom to top is B, C, A. This is determined by comparing their densities, which are calculated using the formula density = mass/volume.
A) A
Fluid A has a mass of 2060g and a volume of 2000mL, resulting in a density of 1.03 g/mL. This relatively high density means Fluid A will settle at the bottom of the beaker.
B) B
Fluid B has a mass of 672g and a volume of 850mL, giving it a density of 0.79 g/mL. This lower density indicates that Fluid B will be the lightest fluid and will rise to the top when the liquids are separated.
C) C
Fluid C has a mass of 990g and a volume of 1100mL, resulting in a density of 0.9 g/mL. This density is greater than that of Fluid B but less than that of Fluid A, which means Fluid C will settle between the two when arranged by density.
D) D
Option D suggests an arrangement of B, A, C. However, since Fluid A is denser than both B and C, it cannot be placed above them in the separation order.
Conclusion
The correct separation order of B, C, A accurately reflects the densities of the fluids, with Fluid B being the least dense and rising to the top, followed by Fluid C, and finally Fluid A at the bottom. All other options fail to accurately represent the correct order based on density calculations.