15. What is the density of iron when 28.5g of iron shot is added to a graduated cylinder containing 45.5mL of water, causing the water level to rise to the 49.1mL mark?
Answer: B
The density of iron is 7.92 g/mL.
To calculate the density of iron, the mass of the iron shot (28.5 g) is divided by the volume of water displaced, which is the difference between the final and initial water levels in the graduated cylinder (49.1 mL - 45.5 mL = 3.6 mL). Thus, the density is calculated as 28.5 g / 3.6 mL = 7.92 g/mL.
A) 0.63 g/mL
This option is incorrect as it does not reflect the proper calculation of density based on the mass and volume provided. Given the mass of iron shot and the volume of water displaced, the resulting density would be significantly higher.
B) 7.92 g/mL
This option is correct because it accurately represents the density calculated from the mass of iron (28.5 g) divided by the volume displaced (3.6 mL). This calculation aligns with the principles of density, confirming that the density of iron is indeed 7.92 g/mL.
C) 0.58 g/mL
This option is incorrect as it does not match the calculated density value. The provided mass and volume indicate a much higher density than 0.58 g/mL, making this option inconsistent with the data.
D) None of the above
This option is incorrect because one of the choices (B) provides the correct density value for iron. Therefore, stating that none of the options are correct is not valid.
Conclusion
The correct answer is definitively 7.92 g/mL, as it is derived directly from the accurate calculation involving the mass of the iron shot and the volume of water displaced. All other options either misrepresent the density calculation or do not align with the principles of density, confirming that they are incorrect.