55. What volume, in mL, of morphine sulfate that comes in 10 mL vials at a concentration of 5 mg/mL will be needed to fill an order for 25 mg?
Answer: D
5 mL of morphine sulfate will be needed to fill an order for 25 mg.
To determine the volume required for 25 mg of morphine sulfate at a concentration of 5 mg/mL, you divide the total desired dose by the concentration: 25 mg ÷ 5 mg/mL = 5 mL.
A) 1
Choosing 1 mL would only provide 5 mg of morphine sulfate, which is insufficient for the order of 25 mg. Therefore, this option is incorrect.
B) 2
Selecting 2 mL would yield only 10 mg of morphine sulfate, which still does not meet the requirement of 25 mg. Thus, this option is also incorrect.
C) 3
Opting for 3 mL would result in 15 mg of morphine sulfate. This amount is still below the necessary 25 mg, making this option incorrect.
D) 5
Using 5 mL provides exactly 25 mg of morphine sulfate, as calculated from the concentration of 5 mg/mL. This is the correct amount needed for the order.
Conclusion
The correct choice is D, as it accurately fulfills the requirement of 25 mg based on the concentration of the morphine sulfate solution. All other options fail to meet the necessary dosage, confirming that only 5 mL is adequate for this specific order.